5u+28=2(1[u+2]1)

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Solution for 5u+28=2(1[u+2]1) equation:


Simplifying
5u + 28 = 2(1[u + 2] * 1)

Reorder the terms:
28 + 5u = 2(1[u + 2] * 1)

Reorder the terms:
28 + 5u = 2(1[2 + u] * 1)

Reorder the terms for easier multiplication:
28 + 5u = 2(1 * 1[2 + u])

Multiply 1 * 1
28 + 5u = 2(1[2 + u])
28 + 5u = 2([2 * 1 + u * 1])
28 + 5u = 2([2 + 1u])
28 + 5u = (2 * 2 + 1u * 2)
28 + 5u = (4 + 2u)

Solving
28 + 5u = 4 + 2u

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-2u' to each side of the equation.
28 + 5u + -2u = 4 + 2u + -2u

Combine like terms: 5u + -2u = 3u
28 + 3u = 4 + 2u + -2u

Combine like terms: 2u + -2u = 0
28 + 3u = 4 + 0
28 + 3u = 4

Add '-28' to each side of the equation.
28 + -28 + 3u = 4 + -28

Combine like terms: 28 + -28 = 0
0 + 3u = 4 + -28
3u = 4 + -28

Combine like terms: 4 + -28 = -24
3u = -24

Divide each side by '3'.
u = -8

Simplifying
u = -8

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